Correct answer: Kb71...Re5[a]/e5 2.Qd7#[A] 1...Re6/e6/[б]/ 2.Qc5#[Б] 1.Rc5? (2.Qd5#) 1...Re5[a]/Rd2 2.Q:e5#[C] 1...e6/[б]/ 2.Qf8#[D] but 1...e5! 1.