Correct answer: Rd31...f5[a] 2.Qf3#[A] 1...c5/[б]/ 2.Bb7#[Б] 1...Nc1[c]/Nc5[d]/Nd2[e]/Nd4[e]/Na1[e]/Na5[e] 2.Nd2#[C] 1...b4[f] 2.Bd3#[E] 1...Nh4/N:f4/N