Correct answer: Qd71...e6[a] 2.Nd6#[A] 1...Nd4/[б]//Ne1/[б]//Ne3/[б]//Nb4/[б]//Na1[c]/Nca3[c] 2.R:d4#[Б] 1...Bg3[d]/Bg5[e]/Bf6[e] 2.Qh7#[C] 1...Nc3/N<