Correct answer: Nc51...Kd5[a] 2.Qb3#[A] 1...d3/[б]/ 2.Ba2#[Б] 1.Bh2? zz 1...Kd5[a] 2.Qb3#[A] 1...d3/[б]/ 2.Ba2#[Б] but 1...c5! 1.Bf2? zz 1...Kd5[a] 2.Q