Correct answer: Bd51...b:c5[a] 2.Re4#[A] 1...Nf1/[б]//Nf5[c]/Ng2/[б]//Ng4/[б]//Nd1/[б]//Nd5[d]/Nc2/[б]/ 2.Rd5#[Б] 1...N:c4[e] 2.Rd3#[C] 1...d6/d5 2.Ne6#[D] 1.
