Correct answer: Qb51...Rc3[a]/Rb1/Ra1/Rd1/Re1/Rf1/Rg1/Rh1 2.Q:c3#[A] 1...Rc4/[б]/ 2.Qd1#[Б] 1...R:e5[c] 2.B:e3#[C] 1...Rc5 2.R:e4# 1.<
