Correct answer: Qb71...Rf1[a]/Rf3/[б]//Rf4/[б]//Rf6/[б]//Rf7/[б]//Rf8/[б]/ 2.Nc2#[A] 1...Rf5[c]/Rc2 2.N:f5#[Б]/Nc2#[A] 1...Re2[d]/Rd2[e]/Rb2/R