Correct answer: Qe51...Rg7+[a] 2.Nc7#[A] 1...Qf7+/[б]/ 2.Q:f7#[Б] 1...Qf6 2.Q:f6# 1.Qd7?? (2.Ng7#/Nd6#/Nc7#[A]) 1...Qf7/[б]/ 2.Q:f7#[Б] 1...R