Correct answer: Nc41...Ba5[a] 2.Q:c5#[A] 1...c6/[б]/ 2.Bc4#[Б] 1...Nd7[c]/Ne4[d]/Ne6[d]/Nb3[d]/Na4[d] 2.Qa4#[C] 1.Kb8? zz 1...Ba5[a] 2.Q:c5#[A] 1..
