Correct answer: Nb71.Nb7! (2.Rb5#/Qc6#/Qb5#/Qc4#/Nb6#) 1...B:c7 2.Qb5# 1...e3/R:b7 2.Qc6# 1...B:b7 2.Rb5# 1...d3 2.Qc4# 1...R:c
