Correct answer: c71...Rd5[a]/Rd8[c] 2.Nc7#[A] 1...Rd7/[б]/ 2.Q:d7#[Б] 1...R:c6 2.Q:c6# 1.Kg8? zz 1...Rd5[a] 2.Nc7#[A] 1...Rd7/[б]/ 2.Q:d7#[Б]
