Correct answer: Qb51...K:e2 2.Q:c2# 1.Qb3?? (2.Qe3#) 1...K:e2 2.Q:c2# 1...Kc1 2.Be3# 1...c1Q/c1R/c1B 2.Qd3# 1...c1N 2.Qb2# bu