Correct answer: Qd11...Ke8[a] 2.Qc6#[A] 1...Kc8/[б]/ 2.Qh3#[Б] 1.Rf7+?? 1...Kc8/[б]/ 2.Qh3#[Б]/Qh8#/Qb7#/Qa8# 1...Ke6 2.Qd5# but 1...Ke8[a]!
