Correct answer: Ra31...c3[a] 2.R:a4#[Б] 1...c5/[б]/ 2.Nfd5#[C] 1...B:c2[c]/Bb5[d] 2.Qa3#[D] 1...Kc3/Bb3 2.Qa5#[A] 1.e4? zz 1...c3[a] 2.R:a4#[Б] 1...c5/[б]/ 2.N