Correct answer: Qf41...Ne2[a]/Nb3/[б]//Na2[c] 2.Q:d3#[A] 1...R:d4[d] 2.R:c2#[Б] 1...R:e3 2.Q:c2#/R:c2#[Б] 1.Ra2? zz 1...Ne2[a]/Nb3/[б]/ 2.Q:d3#[A
