Correct answer: Qh31...Kd4[a]/f4/[б]/ 2.Qf6#[A] 1...e3[c] 2.d4#[Б] 1.Bf3? zz 1...f4/[б]/ 2.Qf6#[A] 1...e:f3/e3[c] 2.d4#[Б] but 1...Kd4[a]! 1.Bd1? zz 1...f4/[б]/ 2.Qf6#[A]
