Correct answer: Bb51...Nf4[a]/Nf8/Ng5/Ng7[a]/Nd4[a]/Nd8/Nc5/N:c7 2.Qd4#[A] 1...e2/[б]/ 2.R:e2#[Б]/Q:e2#[C] 1...Nf3[c]/Ng2/Nd3/Nc2 2.Bd
