Correct answer: Qa21...Nb1[a]/Nc2[a] 2.Nac2#[A] 1...c3/[б]/ 2.Nb3#[Б] 1.Bd6?? zz 1...Nb1[a]/Nc2[a] 2.Nac2#[A] 1...c3/[б]/ 2.Nb3#[Б] but 1...b4! 1.Be7?? zz