Correct answer: Nge31...Nc2[a]/Nc6[a]/Nd5[a]/Na2/[б]//Na6[a] 2.Q:d3#[A] 1...Ng8[c]/Nf5[c]/Nf7[d] 2.Q:g4#[Б] 1...c6/c5 2.Nd6# 1.Bf7? zz 1...Nc2[a]
