Correct answer: Qa51...Ng2[a]/Ng6[a]/Nf3[a]/Nf5[a] 2.Nf3#[A] 1...c3/[б]/ 2.Q:d3#[Б] 1.K:b2?? zz 1...Ng2[a]/Ng6[a]/Nf3[a]/Nf5[a] 2.Nf3#[A] but 1...c3+/[б
