Correct answer: Qc21...Bd4[a]/B:b4/[б]/ 2.Qh3# 1...h4 2.Bg4# 1.Kb6? (2.Ne7#[A]) 1...B:b4/[б]/ 2.Qh3# but 1...Bd4+[a]! 1.Ne8? (2.Nb6#[Б]) 1...B
