Correct answer: Qf81...K:c4[a] 2.e7#[Б] 1...Kd6/K:c6/[б]/ 2.Qd7#[A] 1...K:e4 2.N:c3# 1.Na:c5? zz 1...K:c4[a] 2.e7#[Б] 1...Kd6/K:c6/[б]/ 2.Qd7#[A] but 1.
