Correct answer: Ng11...Rf3[a]/f3[c] 2.Qe6#[A] 1...Re2/[б]/ 2.Q:f4#[Б] 1.Ng5? (2.Qe6#[A]) 1...Rf3[a]/Re2/[б]//Rd2/Rc2/Rb2/Ra2/Rg2/Rh2 2.Q<