Correct answer: Nd51...Bf2[a] 2.Ncb1#[A] 1...Nd3/[б]//Na2[c] 2.Q:e2#[Б] 1.Kh3?? zz 1...Bf2[a] 2.Ncb1#[A] 1...Nd3/[б]//Na2[c] 2.Q:e2#[Б] but 1...g2! 1
