Correct answer: Qg51...Bg4 2.Nd3#[A] 1...Be4 2.N:e6#[Б] 1.Qf6?? (2.Qd4#/Q:e7#) 1...N:b3 2.Qc3# 1...Nb7 2.Qd4#/Qc3# 1...Nc4 2.Qd4#
