Correct answer: Nc51...Nf3[a]/Ng2[a]/Nd3[a] 2.Nd3#[A] 1...N:c2/[б]/ 2.Q:c2#[Б] 1...d3 2.Q:e5# 1.d6? zz 1...Nf3[a]/Ng2[a]/Nd3[a] 2.Nd3#[A] 1...N:c2/
