Correct answer: Nd31...Qb3/Qa3/Qd3[a]/Qe3/Qf3/Qh3/Qe1[c] 2.Q:f6#[Б] 1...Qg3/[б]//Qd4/Qe5[d]/Qb2/Qa1 2.Q:g3#[A] 1...Qc2/Qc1/Qd2/