Correct answer: Bb61...Nb4[a]/Nb8/[б]//Nc5[c] 2.R:b4#[A] 1...d3[d] 2.Rc3#[Б] 1.Bc3?? zz 1...Nb4[a]/Nb8/[б]//Nc5[c] 2.R:b4#[A] 1...d3[d] 2.Ne3#[C] but 1...
