Correct answer: Qc41...Ke5[a] 2.Q:e7#[A] 1...e6/[б]/ 2.Qc7#[Б] 1...e5[c] 2.Qd7#[C] 1...c5 2.Qd5# 1.Na6? zz 1...Ke5[a] 2.Q:e7#[A] 1...e6/[б]/ 2.Qc7#[Б] 1...e5[c]
