Correct answer: Bc51...Kd5[a] 2.Qd4#[A] 1...Nc2/Nc6/Nd3/[б]//Nd5/Na2/Na6 2.Qd3#[Б] 1...Nf2/Nf6 2.R:e5#/Q:e5# 1...N:e3 2.Q:e5# 1.K