Correct answer: Bc31...Rh4/Rh3/Rh2[a]/Rh1 2.Rb4#[Б] 1...N:d4/[б]/ 2.Rb3#[C] 1...Ne1/Ne3[c]/Nb4/Na1/Na3 2.Qe3#[D] 1...Q:c1[d] 2.Rd5#[E] 1.
