Correct answer: Qa51...Ra4[a] 2.Qc5#[A] 1...Rc4/[б]/ 2.Qd6#[Б] 1...Kc4 2.K:e3# 1...B:b2 2.Q:b4# 1.Bg2? zz 1...Ra4[a] 2.Qc5#[A] 1...Rc4/[б]/ 2.