Correct answer: Nc41...Ke4[a] 2.Bf5#[A] 1...e4/[б]/ 2.Bc4#[Б] 1.Bh3? zz 1...Ke4[a] 2.Bf5#[A] 1...e4/[б]/ 2.Bf1#[C] but 1...c2! 1.Bf7? zz 1...Ke4[a] 2.B