Correct answer: Rb11...Kc2[a] 2.Qb1#[A] 1...Kc4/[б]//Be3 2.Qf1#[Б] 1...Be1/Bf4/Bg5/Bh6/Bc1/c2 2.Qd4#[C] 1.Rb4?? zz 1...Kc2[a] 2.Qb1#[A]