Correct answer: Qe51...e6[a]/e5/[б]/ 2.Qh4#[A] 1...Nd5/Ne6[c]/Ne8[c]/Nb5/Na6[d]/Na8 2.Qe8#[Б] 1.Qh2? (2.Q:c7#) 1...e6[a]/e5/[б]/ 2.Qh4#[A] 1...Nd5/