Correct answer: Nf51...Kf4[a] 2.Qd6#[A] 1...K:f6/[б]/ 2.Qd4#[Б] 1.Bd3[C]? zz 1...Kf4[a] 2.Qd6#[A] 1...K:f6/[б]/ 2.Qd4#[Б] but 1...c2! 1.Bf5[D]? zz 1...
