Correct answer: Bg31...Nc4[a] 2.Bc6#[A] 1...Be4/[б]/ 2.Be6#[Б] 1...a6/a5 2.Nb6# 1...Nd1/Nd3/N:a4 2.Qa2# 1...Bf1/Bf3 2.Qf3# 1...d3 2.Nc3# 1.R<