Correct answer: Qb81...Qg2[a]/Qg3[a]/Qg4[a]/Qg5[a]/Qg7/Qg8/[б]/ 2.Q:b5#[A] 1...Qe1/Qd1[c]/Qf2[c]/Qe3[c]/Qd4/Qc5[d] 2.Bg6#[Б] 1...Qg6/Q
