Correct answer: Qh51...N:c1/Nd2[a]/N:d4/[б]//Na1 2.Nb7#[A] 1...Nd5[c] 2.Nc4#[C] 1...N:c5/Nd1/Ne2/Ne4/Nb1/Nb5/N:a2 2.Be5#[Б] 1.B:b
