Correct answer: Nb61...e:d4[a]/e4[a] 2.Bg3#[A] 1...Nc5/[б]//Nc7[c] 2.Qc7#[Б] 1...Ra4/Ra3/Ra2/Ra1 2.N:b5# 1...Nc6/Nd7 2.Q:c6# 1...Bg7 2.f:g7# 1...B