Correct answer: Ne41...Nd3[a]/Nd7/[б]//Ne4[c]/Nb7/[б]//Na4/[б]//Na6/[б]/ 2.R:d3#[Б] 1...Ne6[d] 2.Nf6#[C] 1...Bb1/Bc4/Rb3/Nb3[e] 2.Bc4#[A] 1...B