Correct answer: Nb61...Nb4[a]/Nb8/[б]//Nc7 2.Q:c5#[A] 1...Bf6 2.B:f6# 1...B:g7 2.Q:g7# 1.Qc7? zz 1...Nb4[a]/Nb8/[б]/ 2.Q:c5#[A] 1...Ne4[c]/<
