Correct answer: Bc61...Nf7/Ng4/Nd7/Nc4[a]/Nc6+/[б]/ 2.Nc6#[A] 1...a3 2.Qd2# 1...b2 2.Q:b2# 1.Nbc4[Б]? (2.Qd2#) 1...N:c4[a] 2.Nc6#[A] 1...Nc6
