Correct answer: Bg41...Ne6[a] 2.Bg2#[A] 1...c4/[б]/ 2.Rh5#[Б] 1...Nd6 2.Ne7#/Nb6# 1.Rg4? zz 1...Ne6[a] 2.Bg2#[A] 1...Ke6/c4/[б]/ 2.Rg5#[C] but 1...N<