Correct answer: Be51...Rg5[a] 2.Nf:h4#[A] 1...Nd4/Ne1/[б]//Ne3/[б]//Nb4/[б]//Na1/[б]/ 2.N:d4#[Б] 1...Bh7 2.B:h7# 1.Bh7? zz 1...Rg5[a] 2.Nf:h4#[A]
