Correct answer: Qa11...Nb4[a] 2.Q:b4#[A] 1...Nc3+/[б]/ 2.Q:c3#[Б] 1...Nac1 2.Qb4#[A]/Qc3#[Б] 1...Nbc1/Nc5/N:d4/Na1 2.Nc4#[C] 1...d:c6 2.N:c6# 1...