Correct answer: Na51...d5[a] 2.Qc7#[A] 1...f3/[б]/ 2.Qh2#[Б] 1...Nc6/Nd7/Na6 2.N:c6# 1...Bh7/Bf7 2.Nf7# 1...B:e6 2.R:e6# 1...d3 2.Q:b2# 1.Qc7[A]
