Correct answer: Bc31...Nb3[a] 2.Rde5#[A] 1...Nc4/[б]/ 2.Rd4#[Б] 1...Bc3 2.N:c3# 1...Bd2 2.N:d2# 1...B:c5/Ba3 2.Nc3#/Nd2# 1...Bg6/Bh5 2.Q