Correct answer: Qc61...Qc6[a]/Qc4[c]/Qc3/Qc2/Qc8 2.N:f4#[A] 1...Qc5/[б]/ 2.d:c5#/N:f4#[A] 1...Qd6[d]/Qb8 2.Nc1#[Б] 1...Qe5[e] 2.d:e5#/Nc1#[Б] 1...e5 2.
