Correct answer: Rc51...R:d3[a] 2.Qf4#[Б]/Bf2#[A] 1...Qb3/Qc1 2.N:b3# 1...Q:e1/Q:d3 2.Nb3#/Nc2# 1...Qc2 2.N:c2# 1...b3 2.Qc3# 1...Rf2 2.Q